298K时
Ca(s) + C(s,石墨)+ 3/2O₂(g)= CaCO₃(s) △H1=-1206.8kJ·mol^-1 ①
Ca(s) + 1/2O₂(g)= CaO(s) △H2=-635.1kJ·mol^-1 ②
C(s,石墨)+ O₂(g)= CO₂(g) △H3=-393.5 kJ·mol^-1 ③
计算CaCO₃(s) = CaO(s) + CO₂(g) △H4= ?

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试题解析：


解：Ca(s) + C(s,石墨)+ 3/2O2(g)= CaCO3(s) △H1＝-1206．8kJ·mol-1 ①

Ca(s) + 1/2O2(g)= CaO(s) △H2＝-635．1kJ·mol-1 ② 
C(s,石墨)+ O2(g)= CO2(g) △H3＝-393．5 kJ·mol-1 ③ 

根据盖斯定律将反应②+③-①可得


 CaCO3(s) = CaO(s) + CO2(g) △H4＝+178．2 kJ·mol-1 


故选A

以上为百科题库网整理的关于"298K时<br>Ca(s) + C(s,石墨)+ 3/2O₂(g)= CaCO₃(s) △H1=-1206.8kJ·mol^-1 ①<br>Ca(s) + 1/2O₂(g)= CaO(s) △H2=-635.1kJ·mol^-1 ② <br>C(s,石墨)+ O₂(g)= CO₂(g) △H3=-393.5 kJ·mol^-1 ③ <br>计算CaCO₃(s) = CaO(s) + CO₂(g) △H4= ?"试题答案及解析，如想学习更多化学类竞赛题，欢迎访问www.baiketk.com查看搜索更多相关信息。

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